请问swoole如何编写一个高性能api接口服务？
网友回复
<?php
$serv = new swoole_server('0.0.0.0', 9911, SWOOLE_PROCESS, SWOOLE_SOCK_TCP);
$serv->set(array(
'worker_num' => 4,
'daemonize' => false,
'backlog' => 128,
));
$serv->on('Connect', 'onConnect');
$serv->on('Receive', 'onReceive');
$serv->on('Close', 'onClose');
$serv->start();
/**
*Http建立连接回调函数
*/
function onConnect($serv, $fd) {
echo "Server is running on 0.0.0.0:9911".PHP_EOL;
}
/**
* 开始接受客户端信息回调函数
*/
function onReceive($serv, $fd, $from_id, $data) {
$_username = request($serv, $fd, $data, "username");
$_password = request($serv, $fd, $data, "password");
response($serv, $fd, json_encode(["youname" => $_username]));
}
/**
* 连接关闭后回调函数
*/
function onClose($serv, $fd) {
return false;
}
/**
* 封装response 的内容
*/
function response($serv, $fd, $res_data = '') {
//响应行
$response = array(
'HTTP/1.1 200',
);
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by thinkfuture
我知道答案，我要回答
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