先concat再通过filter对比,代码如下:
let a = [1,3,4], b = [2,3,4];
let c = a.concat(b).filter((cur, i, arr) => {
return arr.indexOf(cur) === arr.lastIndexOf(cur);
});
console.log(c);
网友回复
先concat再通过filter对比,代码如下:
let a = [1,3,4], b = [2,3,4];
let c = a.concat(b).filter((cur, i, arr) => {
return arr.indexOf(cur) === arr.lastIndexOf(cur);
});
console.log(c);
网友回复